How to Calculate the Buckling Load of a Column

Finds the load at which a slender column buckles sideways, from Euler's formula P = π²EI ÷ (kL)². It falls with the square of the length, so a column twice as long carries a quarter of the load. How the ends are held matters just as much.

A slender column fails by bowing sideways long before the material itself is crushed. That is buckling, and this finds the load at which it happens.

P=π2EI(kL)2P = \dfrac{\pi^2 EI}{(kL)^2}

EE is Young's modulus, II the second moment of area, LL the length and kk the effective length factor.

Length counts twice over

The denominator carries the square of the length, so a column twice as long carries a quarter of the load. Length matters far more than thickness here. It is why a thin rod bends easily between your hands but becomes stubbornly stiff once cut short.

How the ends are held

The effective length factor depends on the restraint at each end: 1.0 for pinned at both ends, 0.7 for one fixed and one pinned, 0.5 for both fixed and 2.0 for a cantilever. Fixing both ends halves kk and quadruples the load; a cantilever cuts it to a quarter. The restraint alone spans a factor of sixteen.

Example

A column with a Young's modulus of 8 GPa, a second moment of area of 1013 cm⁴ and a length of 3 m, pinned at both ends, buckles at 88.9 kN. With a cross-section of 110.25 cm² the slenderness ratio is 99 and the buckling stress 8.06 N/mm².

Notes

Euler's formula applies to slender columns. A short, stout column with a low slenderness ratio crushes before it buckles, and its capacity is set by the compressive strength of the material instead.