y=sechxy = \operatorname{sech} x

Graph of the Hyperbolic Secant y=sechxy = \operatorname{sech} x

The hyperbolic secant function y=sechxy = \operatorname{sech} x is defined as the reciprocal of the hyperbolic cosine1.

sechx=1coshx=2ex+ex\operatorname{sech} x = \frac{1}{\cosh x} = \frac{2}{e^x + e^{-x}}

It is the hyperbolic counterpart of the ordinary secant secx\sec x.

Domain and range

  • The domain is all real numbers
  • The range is the half-open interval (0,1](0, 1]
  • The maximum 11 is attained at x=0x = 0
  • It is an even function

The denominator coshx\cosh x is always at least 11 and never 00, so the function is defined for every real number. Since coshx1\cosh x \geq 1, the value stays at 11 or below and never reaches 00. Where secx\sec x had asymptotes and satisfied y1|y| \geq 1, this function is the exact opposite: bounded and smooth.

Symmetry

Since coshx\cosh x is even, its reciprocal sechx\operatorname{sech} x is even too, and the graph is symmetric about the yy-axis.

Monotonicity and maximum

The derivative is ddxsechx=sechxtanhx\dfrac{d}{dx}\operatorname{sech} x = -\operatorname{sech} x \tanh x. As sechx\operatorname{sech} x is positive, the sign comes from tanhx-\tanh x: the function increases for x<0x < 0 and decreases for x>0x > 0. The maximum point is (0,1)(0, 1).

Asymptote and decay

As x±x \to \pm\infty we have coshx\cosh x \to \infty and hence sechx0\operatorname{sech} x \to 0, so the xx-axis is a horizontal asymptote. The values are always positive, so the curve approaches 00 from above.

Far out coshxex2\cosh x \approx \dfrac{e^{|x|}}{2}, so the decay is exponential.

sechx2ex\operatorname{sech} x \approx 2e^{-|x|}
xxsechx\operatorname{sech} x
0011
110.6481\approx 0.6481
220.2658\approx 0.2658
330.0993\approx 0.0993

The graph is a bell shape, symmetric, raised in the middle and falling away smoothly on both sides. It resembles the density of a normal distribution, but its tails decay exponentially rather than as steeply as a Gaussian.

An identity

Dividing both sides of cosh2xsinh2x=1\cosh^2 x - \sinh^2 x = 1 by cosh2x\cosh^2 x gives the following.

1tanh2x=sech2x1 - \tanh^2 x = \operatorname{sech}^2 x

The right-hand side is exactly the derivative of tanhx\tanh x. It corresponds to 1+tan2x=sec2x1 + \tan^2 x = \sec^2 x for trigonometric functions, differing only in a sign.

Applications

The smooth bell shape appears in the soliton solutions of equations describing nonlinear waves2. The profile of a solitary wave is written with sech\operatorname{sech} or sech2\operatorname{sech}^2.

  • Solitons of the KdV equation and of the nonlinear Schrödinger equation
  • Light pulses that travel along an optical fiber without changing shape
  • Solitary waves on shallow water
  1. Hyperbolic functions, Wikipedia
  2. Soliton, Wikipedia