y=arccos⁡xy = \arccos x

Inverse Cosine (Arccosine) y=arccos⁡xy = \arccos x

arccos⁡x\arccos x, the inverse cosine or arccosine, is the inverse of the cosine function cos⁡\cos1. Since cos⁡\cos is periodic too, it is not one-to-one over its whole domain, so it is restricted to the interval [0,π][0, \pi], on which it decreases, and the inverse of that restriction, the principal value, is arccos⁡\arccos.

Definition

y=arccos⁡xy = \arccos x is the value yy satisfying both of the following.

  • cos⁡y=x\cos y = x
  • 0≤y≤π0 \leq y \leq \pi

Domain and range

The domain is the interval [−1,1][-1, 1] and the range is the interval [0,π][0, \pi].

Monotonicity

The derivative is as follows.

ddxarccos⁡x=−11−x2(−1<x<1)\frac{d}{dx}\arccos x = -\frac{1}{\sqrt{1 - x^2}} \quad (-1 < x < 1)

It is always negative, so the function decreases monotonically over its whole domain. It differs from the derivative of the inverse sine only in sign, which reflects the fact that sin⁡\sin and cos⁡\cos run in opposite directions on their chosen intervals.

Symmetry

It is neither odd nor even, but it has point symmetry about (0,π2)\left( 0, \dfrac{\pi}{2} \right).

arccos⁡(−x)=π−arccos⁡x\arccos(-x) = \pi - \arccos x

Notable values

xxarccos⁡x\arccos x
−1-1π\pi
00π2\dfrac{\pi}{2}
12\dfrac{1}{2}π3\dfrac{\pi}{3}
22\dfrac{\sqrt{2}}{2}π4\dfrac{\pi}{4}
32\dfrac{\sqrt{3}}{2}π6\dfrac{\pi}{6}
1100

Tangents at the endpoints

At x=±1x = \pm 1 the denominator of the derivative tends to 00, so the tangent becomes vertical. The graph drops away from (−1,π)(-1, \pi) and comes to rest at (1,0)(1, 0).

Relation to the inverse sine

arcsin⁡x+arccos⁡x=π2\arcsin x + \arccos x = \frac{\pi}{2}

So arccos⁡x=π2−arcsin⁡x\arccos x = \dfrac{\pi}{2} - \arcsin x, and the graph of arccos⁡\arccos is that of arcsin⁡\arcsin turned upside down and lifted by π2\dfrac{\pi}{2}.

Itemarcsin⁡x\arcsin xarccos⁡x\arccos x
Domain[−1,1][-1, 1][−1,1][-1, 1]
Range[−π2,π2]\left[ -\dfrac{\pi}{2}, \dfrac{\pi}{2} \right][0,π][0, \pi]
Behaviorincreasingdecreasing
Center of symmetry(0,0)(0, 0)(0,π2)\left( 0, \dfrac{\pi}{2} \right)

Applications

When the angle between two vectors is found from their dot product, arccos⁡\arccos is what turns the value of cos⁡θ\cos\theta back into the angle θ\theta.

θ=arccos⁡a⃗⋅b⃗∣a⃗∣∣b⃗∣\theta = \arccos\frac{\vec{a} \cdot \vec{b}}{|\vec{a}||\vec{b}|}

It appears constantly in geometry, physics and computer graphics.

  1. Inverse trigonometric functions, Wikipedia