Focus and directrix of a parabola

Find the focus and directrix of the parabola y=x24y = \dfrac{x^2}{4}1. Rewriting it as x2=4yx^2 = 4y matches the form x2=4pyx^2 = 4py with p=1p = 1, so the focus is (0,1)(0, 1) and the directrix is the line y=1y = -1.

Equidistance

Every point on the parabola is equidistant from the focus and the directrix.

Point on the curveDistance to the focusDistance to the directrix
(0,0)(0, 0)1111
(2,1)(2, 1)2222
(4,4)(4, 4)5555

The definition gives the equation

That equidistance is in fact the definition of a parabola. If a point (x,y)(x, y) is equidistant from the focus and the directrix, then the following holds.

x2+(y1)2=y+1\sqrt{x^2 + (y - 1)^2} = |y + 1|

Squaring both sides gives x2+y22y+1=y2+2y+1x^2 + y^2 - 2y + 1 = y^2 + 2y + 1; the y2y^2 and the 11 cancel, leaving x2=4yx^2 = 4y. The equation of a parabola is nothing but this equidistance rewritten. Just as a circle is defined by equal distance from a center, a parabola is defined by equal distance from a point and a line.

How wide the parabola opens

The points (2,1)(2, 1) and (2,1)(-2, 1) are the ends of the chord through the focus perpendicular to the axis. Its length is 4p=44p = 4, and it measures how widely the parabola opens: the larger pp, the farther the focus and the broader the curve.

ParabolappFocusDirectrix
y=x2y = x^214\dfrac{1}{4}(0,14)\left(0, \dfrac{1}{4}\right)y=14y = -\dfrac{1}{4}
y=x24y = \dfrac{x^2}{4}11(0,1)(0, 1)y=1y = -1

Why it is called the focus

The name comes from optics. Every ray arriving parallel to the axis is reflected by the parabola through that single point2.

  • Satellite dishes and reflecting telescopes gather parallel rays into the focus
  • Run backwards, a source at the focus sends out rays parallel to the axis
  • That is how the reflector behind a headlight or a flashlight bulb works

The large dots mark the focus and the two ends of the chord through it.

  1. Parabola, Wikipedia
  2. Parabolic reflector, Wikipedia