The length of a curve is also found with a definite integral1. We compute the length of y=32x3/2 over 0≤x≤3.
It starts from the Pythagorean theorem
Replacing the curve by a fine polyline, one segment has length Δx2+Δy2. Factoring out Δx turns it into 1+(ΔxΔy)2Δx, and summing and taking the limit gives the formula.
L=∫ab1+f′(x)2dx
The formula for length is the formula for the distance between two points, chopped fine and added up.
Working it out
For this function f′(x)=x1/2, so 1+f′(x)2=1+x and the inside of the root comes out clean.
L=∫031+xdx=[32(1+x)3/2]03=32(8−1)=314
Quantity
Value
Length of the curve
314≈4.667
The segment joining the ends
21≈4.583
The curve is a little longer than the segment, which also confirms that the shortest path between two points is a straight line.
Checking against a line
For y=x we have f′=1, so L=∫0a2dx=2a, matching the distance from the origin to (a,a). The formula returns the obvious answer properly.