The length of a curve

The length of a curve is also found with a definite integral1. We compute the length of y=23x3/2y = \dfrac{2}{3}x^{3/2} over 0x30 \leq x \leq 3.

It starts from the Pythagorean theorem

Replacing the curve by a fine polyline, one segment has length Δx2+Δy2\sqrt{\Delta x^2 + \Delta y^2}. Factoring out Δx\Delta x turns it into 1+(ΔyΔx)2Δx\sqrt{1 + \left( \dfrac{\Delta y}{\Delta x} \right)^2}\,\Delta x, and summing and taking the limit gives the formula.

L=ab1+f(x)2dxL = \int_a^b \sqrt{1 + f'(x)^2}\,dx

The formula for length is the formula for the distance between two points, chopped fine and added up.

Working it out

For this function f(x)=x1/2f'(x) = x^{1/2}, so 1+f(x)2=1+x1 + f'(x)^2 = 1 + x and the inside of the root comes out clean.

L=031+xdx=[23(1+x)3/2]03=23(81)=143L = \int_0^3 \sqrt{1 + x}\,dx = \left[ \frac{2}{3}(1 + x)^{3/2} \right]_0^3 = \frac{2}{3}(8 - 1) = \frac{14}{3}
QuantityValue
Length of the curve1434.667\dfrac{14}{3} \approx 4.667
The segment joining the ends214.583\sqrt{21} \approx 4.583

The curve is a little longer than the segment, which also confirms that the shortest path between two points is a straight line.

Checking against a line

For y=xy = x we have f=1f' = 1, so L=0a2dx=2aL = \int_0^a \sqrt{2}\,dx = \sqrt{2}\,a, matching the distance from the origin to (a,a)(a, a). The formula returns the obvious answer properly.

When the computation turns hard

CurveIntegral for the lengthResult
y=23x3/2y = \dfrac{2}{3}x^{3/2}1+xdx\int\sqrt{1+x}\,dxelementary
y=x2y = x^21+4x2dx\int\sqrt{1+4x^2}\,dxinvolves a logarithm
An ellipsenot expressible in elementary functions2

When the inside of the root is not a square, the computation becomes hard. An integral for a length is a far tougher opponent than one for an area.

The circumference of a circle

For y=r2x2y = \sqrt{r^2 - x^2} we have f=xr2x2f' = -\dfrac{x}{\sqrt{r^2 - x^2}} and 1+f2=rr2x2\sqrt{1 + f'^2} = \dfrac{r}{\sqrt{r^2 - x^2}}. Integrating that from r-r to rr gives πr\pi r, the correct length of a semicircle.

The curve rising to the upper right is y=23x3/2y = \dfrac{2}{3}x^{3/2}, the curve above it is the integrand y=1+xy = \sqrt{1 + x}, and the large dots are the two ends.

  1. Arc length, Wikipedia
  2. Elliptic integral, Wikipedia